0.6*n^2+n^2=0

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Solution for 0.6*n^2+n^2=0 equation: 



0.6n^2+n^2=0

We add all the numbers together, and all the variables

1.6n^2=0

a = 1.6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1.6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{3.2}=0$

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